A) \[4\sqrt{3}\]
B) \[\frac{4\sqrt{3}}{3}\]
C) \[3\sqrt{2}\]
D) 4
Correct Answer: A
Solution :
Here, p(Probability of getting white ball)\[=\frac{30}{40}=\frac{3}{4}\] \[\therefore \]\[q=\frac{1}{4}\]and\[n=16\] Now, mean\[=np=16.\frac{3}{4}=12\] Standard deviation \[=\sqrt{npq}=\sqrt{16.\frac{3}{4}.\frac{1}{4}}=\sqrt{3}\] \[\therefore \]\[\frac{Mean\,of\,X}{Standard\text{ }deviation\text{ }of}=\frac{12}{\sqrt{3}}=4\sqrt{3}\]You need to login to perform this action.
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