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JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Evening)

  • question_answer
    Let K be the set of all real values of x where the function\[f(x)=\sin |x|-|x|+2(x-\pi )\]is not differentiable. Then the set K is equal to [JEE  Main Online Paper (Held on 11-jan-2019 Evening)]

    A) \[\{\pi \}\]                                 

    B) \[\left\{ 0 \right\}\]

    C) \[\phi \](an empty set)   

    D)               \[\{0,\pi \}\]

    Correct Answer: C

    Solution :

    Here,\[f(x)=sin|x|-|x|+2(x-\pi )cos|x|\] \[\because \]\[\sin |x|-|x|\]is differentiable function at x = 0 \[\therefore \]\[K=\phi \](an empty set)


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