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JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Morning)

  • question_answer
    A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Considering only translational and rotational modes, the total internal energy of the system is [JEE Main Online Paper (Held On 11-Jan-2019 Morning]

    A) 20 RT                           

    B) 12 RT

    C) 4 RT    

    D)                  15 RT

    Correct Answer: D

    Solution :

    Here, oxygen molecule has three translational and two rotational degree of freedom whereas an argon atom has three translational degree of freedom only. As each translational and rotational degree of freedom corresponds to energy \[\frac{1}{2}\]RT for 1 mole. So total internal energy of the system is \[({{n}_{1}}{{f}_{1}}+{{n}_{2}}{{f}_{2}})\frac{1}{2}RT=\{3(3+2)+5(3)\}\frac{1}{2}RT\]\[=15RT\]


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