A) 1 cup of water to 3 cups of pure milk
B) 2 cups of water to 3 cups of pure milk
C) 1 cup of water to 2 cups of pure milk
D) 3 cups of water to 2 cups of pure milk
Correct Answer: D
Solution :
Freezing point of pure milk\[=-{{0.5}^{o}}C,\Delta {{T}_{f}}=0.5\] Freezing point of diluted milk\[=-{{0.2}^{o}}C,\Delta {{T}_{f}}=0.2\] \[\frac{{{(\Delta {{T}_{f}})}_{1}}}{{{(\Delta {{T}_{f}})}_{2}}}=\frac{0.5}{0.2}=\frac{{{K}_{f}}{{m}_{1}}}{{{K}_{f}}{{m}_{2}}}\] Both have same value of state. Let, that be x mole. \[\frac{0.5}{0.2}=\frac{x\,mole\times \,{{w}_{2}}}{{{w}_{f}}\times x\,mole}\] \[\frac{5}{2}=\frac{\,{{w}_{2}}}{{{w}_{1}}}\] \[{{w}_{2}}=\frac{5}{2}{{w}_{1}}\]
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