A) \[Blamer,\,\infty \to 2\]
B) \[Paschen,\,\infty \to 3\]
C) \[Lyman,\,\infty \to 1\]
D) \[Paschen,\,5\to 3\]
Correct Answer: B
Solution :
\[\frac{1}{\lambda }={{R}_{H}}\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)={{10}^{7}}\left( \frac{1}{{{3}^{2}}}-\frac{1}{\infty } \right)\] \[\lambda =9\times {{10}^{-7}}m\] \[\therefore \] \[\lambda =900nm\]
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