A) \[\frac{7}{10}\]
B) \[\frac{3}{5}\]
C) \[\frac{2}{5}\]
D) \[\frac{1}{2}\]
Correct Answer: C
Solution :
Since, sum of two numbers is even, so either both the numbers are even or both are odd. So, the required probability\[=\frac{^{5}{{C}_{2}}}{^{5}{{C}_{2}}{{+}^{6}}{{C}_{2}}}\] \[=\frac{10}{10+15}=\frac{2}{5}\]
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