JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Afternoon)

  • question_answer
    Consider the LR circuit shown in the figure. If the switch S is closed at t = 0 then the amount of charge that passes through the battery between t = 0 and \[t=\frac{L}{R}\]is [JEE Main 12-4-2019 Afternoon]

    A) \[\frac{EL}{7.3{{R}^{2}}}\]                      

    B) \[\frac{EL}{2.7{{R}^{2}}}\]

    C) \[\frac{7.3EL}{{{R}^{2}}}\]                      

    D) \[\frac{2.7EL}{{{R}^{2}}}\]

    Correct Answer: B

    Solution :

    \[q=\int_{{}}^{{}}{Idt}\]           \[q=\int\limits_{0}^{L/R}{\frac{E}{R}}\left[ 1-{{e}^{\frac{-Rt}{L}}} \right]dt\]           \[q=\frac{EL}{{{R}^{2}}}\frac{1}{e}\] \[q=\frac{EL}{2.7{{R}^{2}}}\]


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