question_answer

In the given circuit, the charge on \[4\mu F\]capacitor will be: [JEE Main 12-4-2019 Afternoon]

A) \[5.4\mu C\]                

B) \[24\mu C\]

C) \[13.4\mu C\]              

D) \[9.6\mu C\]

Correct Answer: B

Solution :

So total charge flow \[=q=5.4\mu F\times 10V\] \[=54\mu C\] The charge will be distributed in the ratio of capacitance \[\Rightarrow \frac{{{q}_{1}}}{{{q}_{2}}}=\frac{2.4}{3}=\frac{4}{5}\] \[\therefore \]\[9X=54\mu C\Rightarrow X=6\mu C\] \[\therefore \]charge on \[4\mu F\]capacitor will be \[=4X=4\times 6\mu C\] \[=24\mu C\]