JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Afternoon)

  • question_answer
    Two sources of sound \[{{S}_{1}}\] and \[{{S}_{2}}\] produce sound waves of same frequency 660 Hz. A listener is moving from source \[{{S}_{1}}\]towards \[{{S}_{2}}\] with a constant speed u m/s and he hears 10 beats/s. The velocity of sound is 330 m/s. Then, u equals: [JEE Main 12-4-2019 Afternoon]

    A) 2.5 m/s

    B) 15.0 m/s

    C) 5.5 m/s            

    D)   10.0 m/s

    Correct Answer: A

    Solution :

                \[f=660\text{ }Hz,v=330\text{ }m/s\]                     \[{{f}_{1}}=f\left( \frac{\text{v}-u}{\text{v}} \right)\] \[{{f}_{2}}=f\left( \frac{\text{v+}u}{\text{v}} \right)\]           \[{{f}_{2}}-{{f}_{1}}=\frac{f}{\text{v}}[v+u-(v-u)]\]           \[10={{f}_{2}}-{{f}_{1}}=\frac{f}{\text{v}}[2u]\] \[u=2.5m/s\]   


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