question_answer

  In the following skew conformation of ethane, H'-C-C-H" dihedral angle is: [JEE Main 12-4-2019 Afternoon]

A) \[120{}^\text{o}\]                

B) \[58{}^\text{o}\]

C) \[149{}^\text{o}\]

D) \[151{}^\text{o}\]

Correct Answer: C

Solution :

\[H'CCH''\] Hence angle between \[H'CCH''\] is \[\left( 120{}^\text{o}+29{}^\text{o} \right)=149{}^\text{o}\]