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JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Afternoon)

  • question_answer
    A person throws two fair dice. He wins Rs. 15 for throwing a doublet (same numbers on the two dice), wins Rs.12 when the throw results in the sum of 9, and loses Rs. 6 for any other outcome on the throw. Then the expected gain/loss (in Rs.) of the person is : [JEE Main 12-4-2019 Afternoon]

    A) \[2gain\]

    B)               \[\frac{1}{2}loss\]

    C) \[\frac{1}{4}loss\]                  

    D) \[\frac{1}{2}gain\]

    Correct Answer: B

    Solution :

    win \[Rs.15\to \]number of cases = 6 win \[Rs.12\to \]number of cases = 4 loss \[Rs.6\to \] number of cases = 26 p(expected gain/loss) \[=15\times \frac{6}{36}+12\times \frac{4}{36}-\] \[6\times \frac{26}{36}=-\frac{1}{2}\]


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