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JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is \[\text{6600}\overset{\text{o}}{\mathop{\text{A}}}\,\], then wavelength of first maximum will be:   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) \[\text{3300}\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B) \[\text{4400}\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[\text{5500}\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D) \[\text{6600}\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

    In a single slit experiment, For diffraction maxima, \[a\sin \theta =(2n+1)\frac{\lambda }{2}\]and for diffraction minima, \[a\sin \theta =n\lambda \] According to question, \[(2\times 1+1)\frac{\lambda }{2}=1\times 6600\] \[(\because {{\lambda }_{R}}=6600{A})\]                         \[\lambda =\frac{6600\times 2}{3}\] \[\lambda =4400{A}\]


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