A) \[{{N}^{-3}}\]
B) \[N_{3}^{-}\]
C) \[N_{2}^{-}\]
D) \[HN_{3}^{-}\]
Correct Answer: B
Solution :
\[\underset{Hydrazoic\,acid}{\mathop{{{N}_{3}}H}}\,N_{3}^{-}+{{H}^{+}}\]i.e, conjugate base of hydrazoic acid is \[N_{3}^{-}.\]
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