JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    The standard enthalpy of formation \[({{\Delta }_{f}}{{H}^{o}}_{298})\]for methane, \[C{{H}_{4}}\]is\[-74.9kJ\,mo{{l}^{-1}}.\]In order to calculate the average energy given out in the formation of a C ? H bond from this it is necessary to know which one of the following?   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) The dissociation energy of the hydrogen molecule, \[{{H}_{2}}\].

    B) The first four ionisation energies of carbon.

    C) The dissociation energy of \[{{H}_{2}}\]and enthalpy and sublimation of carbon (graphite).

    D) The first four ionisation energies of carbon and electron affinity of hydrogen.

    Correct Answer: A

    Solution :

                    To calculate average enthalpy of C ? H bond in methane following in formations are (i) needed dissociation energy of \[{{H}_{2}}\] i.e. \[\frac{1}{2}{{H}_{2}}(g)\xrightarrow[{}]{{}}H(g);\Delta H=x\](suppose) (ii) Sublimation energy of C(graphite) to C(g) \[C(graphite)\xrightarrow[{}]{{}}C(g);\Delta H=y(Suppose)\] Given \[C(graphite)+2{{H}_{2}}(g)\xrightarrow[{}]{{}}C{{H}_{4}}(g);\Delta H=75kJ\,mo{{l}^{-1}}\]


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