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JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Evening)

  • question_answer
    Two satellites, A and B, have masses m and 2 m respectively. A is in a circular orbit of radius R, and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, \[\frac{{{T}_{A}}}{{{T}_{B}}},\]is [JEE Main Online Paper Held On 12-Jan-2019 Evening]

    A) 1                                 

    B) 2     

    C) \[\sqrt{\frac{1}{2}}\]                             

    D)   \[\frac{1}{2}\]

    Correct Answer: A

    Solution :

    The velocity of the satellite is\[\sqrt{\frac{GM}{r}}.\] \[\therefore \] \[\frac{{{T}_{A}}}{{{T}_{B}}}=\frac{\frac{1}{2}{{m}_{A}}v_{A}^{2}}{\frac{1}{2}{{m}_{B}}v_{B}^{2}}=\frac{1}{2}\times \frac{2R}{R}=1\]


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