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JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Evening)

  • question_answer
    The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 B.M. The suitable ligand for this complex is [JEE Main Online Paper Held On 12-Jan-2019 Evening]

    A) \[NC{{S}^{-}}\]                                  

    B) \[C{{N}^{-}}\]

    C) CO                              

    D)   ethylenediamine

    Correct Answer: A

    Solution :

    \[\mu =\sqrt{n(n+2)}=5.9B.M.\]\[\Rightarrow n=5\](Where, n = no. of unpaired electrons] \[M{{n}^{2+}}=[Ar]3{{d}^{5}}\] Five unpaired electrons in 3d-orbital are possible under influence of only weak field ligand. Among the given, \[NC{{S}^{-}}\]is relatively weak.


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