JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Evening)

  • question_answer
    Given:
    (i)\[{{C}_{(graphite)}}+{{O}_{2(g)}}\to C{{O}_{2(g)}};{{\Delta }_{r}}{{H}^{o}}=xkJ\,mo{{l}^{-1}}\]
    (ii)\[{{C}_{(graphite)}}+\frac{1}{2}{{O}_{2(g)}}\to C{{O}_{(g)}};\]\[{{\Delta }_{r}}{{H}^{o}}=y\,\,kJ\,\,mo{{l}^{-1}}\]
    (iii)\[C{{O}_{(g)}}+\frac{1}{2}{{O}_{2(g)}}\to C{{O}_{2}}_{(g)};{{\Delta }_{r}}{{H}^{o}}=z\,\,kJ\,\,mo{{l}^{-1}}\]
    Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct? [JEE Main Online Paper Held On 12-Jan-2019 Evening]

    A) \[z=x+y\]                                 

    B) \[x=y-z\]

    C) \[x=y+z\]                     

    D)   \[y=2zx\]

    Correct Answer: C

    Solution :

    By adding equation (ii) and (iii), we get \[C(graphite)+{{O}_{2(g)}}\to C{{O}_{2(g)}},\]i.e.,\[x=y+z\]


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