A)
B)
C)
D)
E) None of these
Correct Answer: E
Solution :
\[\frac{dV}{dt}=\cos nt.\]or,\[\frac{d\left( \frac{4}{3}\pi {{r}^{3}} \right)}{dt}=K\] \[\frac{4}{3}\pi (3{{r}^{2}})\frac{dr}{dt}=K,4\pi {{r}^{2}}\frac{dr}{dt}=K\] \[\Rightarrow \]\[{{r}^{3}}=Kt+C\Rightarrow r={{K}_{1}}{{t}^{1/3}}+{{C}_{1}}\] The excess pressure inside the bubble is\[\frac{4S}{r}\] i.e. \[{{P}_{excess}}\propto \frac{1}{r}\]pressure, \[P={{P}_{0}}+\frac{4S}{r}\]\[={{P}_{0}}+\frac{4S}{{{K}_{1}}{{t}^{1/3}}+{{C}_{1}}}\] * None of the given options is correct.
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