JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Morning)

  • question_answer
    For the given cyclic process CAB as shown for a gas, the work done is        [JEE Main Online Paper Held On 12-Jan-2019 Morning]

    A) 10 J                                         

    B) 1 J

    C) 5 J                               

    D)   30 J

    Correct Answer: A

    Solution :

    CA= change in volume \[\Delta V=(5-1)=4{{m}^{3}}AB=\]change in pressure \[\Delta P=(6-1)=5{{m}^{3}}\] Work done = Area of \[\Delta ABC=\frac{1}{2}\times AB\times CA\] \[W=\frac{1}{2}\times 4\times 5=10J\]


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