2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held On 12 May 2012)

  • question_answer
    The radius of a calcium ion is 94 pm and of the oxide ion is 146 pm. The possible crystal structure of calcium oxide will be     JEE Main Online Paper (Held On 12 May 2012)

    A) tetrahedral        

    B)                        trigonal

    C)                        octahedral       

    D)                        pyramidal

    Correct Answer: C

    Solution :

                    As per formula,\[\text{radius}\,\text{=}\frac{\text{radius}\,\text{of}\,\text{cation}}{\text{radius}\,\text{of}\,\text{anion}}\] \[\,\text{=}\frac{94}{146}=0.643\] Since the value is between 0.414 - 0.732 hence the coordination no. will be 6 and geometry will be octahedral.                


You need to login to perform this action.
You will be redirected in 3 sec spinner