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JEE Main & Advanced JEE Main Paper (Held On 12 May 2012)

  • question_answer
    The ppm level of \[{{F}^{-}}\]in a 500 g sample of a tooth paste containing 0.2 g \[{{F}^{-}}\]is     JEE Main Online Paper (Held On 12 May 2012)

    A) 400   

    B)                        1000

    C)                        250                                        

    D)                        200

    Correct Answer: A

    Solution :

                     \[ppm=\frac{wt.\,of\,solute}{wt.\,of\,solvent}\times {{10}^{6}}\] \[=\frac{0.2}{500}\times {{10}^{6}}=400\]                                


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