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JEE Main & Advanced JEE Main Paper (Held On 12 May 2012)

  • question_answer
    5 g of benzene on nitration gave 6.6 g of nitrobenzene. The theoretical yield of the nitrobenzene will be     JEE Main Online Paper (Held On 12 May 2012)

    A) 4.5 g                                      

    B)                        5.6g

    C)                        8.09g                                    

    D)                        6.6g

    Correct Answer: C

    Solution :

                    \[\underset{78g}{\mathop{{{C}_{6}}{{H}_{6}}}}\,+HN{{O}_{3}}\to \underset{123g}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,+{{H}_{2}}O\] Now since 78g of benzene on nitration give = 123g nitrobenzene hence 5g of benzene on nitration give \[=\frac{123}{78}\times 5=7.88g\]nearest answer is (c) i.e. theoretical yield =7.88g


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