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JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    A body of mass \[m\] is moving in a circular orbit of radius R about a planet of mass M. At some instant, it splits into two equal masses. The first mass moves in a circular orbit of radius \[\frac{R}{2}\], and the other mass, in a circular orbit of radius \[\frac{3R}{2}\]. The difference between the final initial total energies is:                   [JEE Online 15-04-2018]

    A) \[-\frac{GMm}{2R}\]             

    B) \[+\frac{GMm}{6R}\]                       

    C) \[-\frac{GMm}{6R}\]             

    D) \[\frac{GMm}{2R}\]

    Correct Answer: C

    Solution :

    Initial energy= \[-\frac{GMm}{R}+\frac{1}{2}\frac{GMm}{R}=-\frac{GMm}{2R}\] Final energy\[=-\frac{GMm/2}{2R/2}-\frac{-GMm/2}{2\times 3R/2}\] \[\Delta E=-\frac{GMm}{6R}\]


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