JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    A force of \[40N\]acts on a point \[B\] at the end of an L-shaped object, as shown in the figure. The angle \[0\] that will produce maximum moment of the force about point \[A\] is given by: [JEE Online 15-04-2018]

    A) \[\tan \theta =\frac{1}{4}\]                

    B) \[\tan \theta =2\]         

    C) \[\tan \theta =\frac{1}{2}\]                

    D) \[\tan \theta =4\]         

    Correct Answer: C

    Solution :

    Moment of force about point A will be given as \[\tau =F\cos \theta \times 4+F\sin \theta \times 2\] For maximum\[\tau \], \[\frac{d\tau }{d\theta }=0\] \[0=-4F\,\,\sin \theta +2F\cos \theta \] \[\tan \theta =\frac{1}{2}\]


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