A) \[4N{{H}_{3}}(g)+5{{O}_{2}}(g)4NO(g)+6{{H}_{2}}O(l)\]
B) \[2N{{O}_{2}}(g)2NO(g)+{{O}_{2}}(g)\]
C) \[{{H}_{2}}(g)+{{I}_{2}}(g)2Hl(g)\]
D) \[3{{O}_{2}}(g)2{{O}_{3}}(g)\]
Correct Answer: A
Solution :
Increase in volume will favour formation of product, if number of moles of reactant is greater than product. In \[3{{O}_{2}}2{{O}_{3}}(g)\], the condition is satisfied. Hence, \[3{{O}_{2}}2{{O}_{3}}\] is the answer.
You need to login to perform this action.
You will be redirected in
3 sec
