A) \[3.2\]
B) \[2.5\]
C) \[4.1\]
D) \[5\]
Correct Answer: C
Solution :
The half life\[{{t}_{1/2}}=10\] days The decay constant\[k=\frac{0.693}{{{l}_{1/2}}}=\frac{0.693}{10days}=0.0693da{{y}^{-1}}\] The time required for one fourth conversion \[t=\frac{2.303}{k}{{\log }_{10}}\frac{a}{a-x}\] \[t=\frac{2.303}{0.0693da{{y}^{-1}}}{{\log }_{10}}\frac{1}{1-(1/4)}\] \[t=4.1days\]
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