A) \[\text{4 }\!\!\times\!\!\text{ 0}\text{.529}\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[\text{2 }\!\!\pi\!\!\text{ }\!\!\times\!\!\text{ 0}\text{.529}\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[\frac{\text{0}\text{.529}}{\text{2 }\!\!\pi\!\!\text{ }}\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[\text{0}\text{.529}\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: B
Solution :
The de-Broglie's wavelength of electron present in first Bohr orbit of 'H' atom is \[\text{2}\pi \times 0.529\overset{o}{\mathop{A}}\,\]. First Bohr orbit of 'H' atom has radius\[r=0.529\overset{o}{\mathop{A}}\,\] Also, the angular momentum is quantised. \[mvr=\frac{h}{2\pi }\] \[2\pi r=\frac{h}{mv}=\lambda \] \[\lambda =2\pi \times 0.529\overset{o}{\mathop{A}}\,\]
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