The reading in an ideal ammeter will be:
JEE Main Online Paper (Held On 19 April 2016)
A) 0.45 A
B) 0.90 A
C) 1.35 A
D) 1.80 A
Correct Answer: C
Solution :
Current in each bulb \[=\frac{\text{Power}}{\text{Voltage}}\] \[=\frac{100}{220}=0.45A\] Current through ammeter \[=0.45\times 3=1.35A\]
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