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JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

  • question_answer
    Consider a cylinder of mass M resting on a rough horizontal rug that is pulled out from under it with acceleration ?a? perpendicular to the axis of the cylinder. What is F friction at point P? It is assumed that the cylinder does not slip.     JEE Main Online Paper (Held On 19 April 2016)

    A) Mg                                        

    B) Ma

    C) \[\frac{Ma}{2}\]                                              

    D) \[\frac{Ma}{3}\]

    Correct Answer: D

    Solution :

    Force of friction at point P, friction \[{{\text{F}}_{\text{friction}}}=\frac{1}{3}Ma\,\sin \theta \] \[=\frac{1}{3}Ma\,\sin {{90}^{o}}\]                         \[[\text{here}\,\theta ={{90}^{o}}]\] \[=\frac{Ma}{3}\]


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