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JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

  • question_answer
    An octahedral complex with molecular composition \[N{{H}_{3}}.Cl.S{{O}_{4}}\]has two isomers, A and B. The solution of A gives a white precipitate with \[AgN{{O}_{3}}\] solution and the solution of B gives white precipitate with \[BaC{{l}_{2}}\] solution. The type of isomerism exhibited by the complex is:     JEE Main Online Paper (Held On 19 April 2016)

    A) Linkage isomerism

    B) Ionisation isomerism

    C) Coordinate isomerism

    D) Geometrical isomerism

    Correct Answer: B

    Solution :

    The two possible isomers for the given octahedral complex are \[[M{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]Cl\] and \[[M{{(N{{H}_{3}})}_{5}}Cl]S{{O}_{4}}.\]They respectively give chloride ion (indicated by precipitation with \[BaC{{l}_{2}})\] and \[S{{O}_{4}}\] ion (indicated by precipitation with \[AgN{{O}_{3}}).\] Hence the type of isomerism exhibited by the complex is ionization isomerism.


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