question_answer

Nickel (Z = 28) combines with a uninegative monodentate ligand to form a diamagnetic complex \[{{[Ni{{L}_{4}}]}^{2-}}.\]The hybridisation involved and the number of unpaired electrons present in the complex are respectively:   JEE Main Online Paper (Held On 19 April 2016)

A) \[s{{p}^{3}},\] two                          

B) \[ds{{p}^{2}},\]zero

C) \[ds{{p}^{2}},\]one                        

D) \[s{{p}^{3}},\]zero

Correct Answer: A

Solution :

\[{{[Ni{{L}_{4}}]}^{2-}}\] i.e, no. of unpaired electron = 2 hybridization \[-s{{p}^{3}}.\]