A) no solution
B) exactly one solution
C) exactly two solution
D) exactly four solution
Correct Answer: A
Solution :
Consider \[\sqrt{3{{x}^{2}}+x+5}=x-3\] Squaring both the sides, we get \[3{{x}^{2}}+x+5={{(x-3)}^{2}}\] \[\Rightarrow \]\[3{{x}^{2}}+x+5={{x}^{2}}+9-6x\] \[\Rightarrow \]\[2{{x}^{2}}+7x-4=0\] \[\Rightarrow \]\[2{{x}^{2}}+8x-x-4=0\] \[\Rightarrow \]\[2x(x+4)-1(x+4)=0\] \[\Rightarrow \]\[x=\frac{1}{2}\]or\[x=-4\] For \[x=\frac{1}{2}\]and\[x=-4\] L.H.S. \[\ne \]R.H.S. of equation, \[\sqrt{3{{x}^{2}}+x+}=x-3\] Also, for every of the given equation. \[\therefore \]Given equation has no solution.
You need to login to perform this action.
You will be redirected in
3 sec
