A) 10
B) 20
C) 15
D) 12
Correct Answer: A
Solution :
Median is given as\[M=l\frac{\frac{N}{2}-F}{f}\times C\]where \[l=\] lower limit of the median - class f = frequency of the median class N = total frequency F = cumulative frequency of the class just before the median class C = length of median class Now, given, \[M=25,N=100,F=45,\] \[C=20-30=10,l=20.\] \[\therefore \]By using formula, we have \[25=20+\frac{50-45}{f}\times 10\] \[25-20=\frac{50}{f}\Rightarrow 5=\frac{50}{f}\Rightarrow f=10\]You need to login to perform this action.
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