A) 96
B) 128
C) 24
D) 72
Correct Answer: A
Solution :
There are 2 vowels and 4 consonants in the letters a, b, c, d, e,f. If we select one vowel, then number of arrangements \[{{=}^{2}}{{C}_{1}}{{\times }^{4}}{{C}_{2}}\times 3!=2\times \frac{4\times 3}{2}\times 3\times 2=72\] If we select two vowels, then number of arrangements\[{{=}^{2}}{{C}_{2}}{{\times }^{4}}{{C}_{1}}\times 3!=1\times 4\times 6=24\] Hence, total number of arrangements \[=\text{72}+\text{24}=\text{96}\]
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