2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

  • question_answer
    Which of the plots shown in the figure represents speed (v) of the electron in a hydrogen atom as a function of the principal quantum number (n)?   JEE Main Online Paper (Held On 26-May-2012)  

    A)  B

    B)                        D

    C)                        C                                            

    D)                        A

    Correct Answer: A

    Solution :

                    Velocity of electron in \[{{n}^{th}}\] orbit of hydrogen atom is given by :\[{{V}_{n}}=\frac{2\pi KZ{{e}^{2}}}{nh}\]Substituting the values we get,\[{{V}_{n}}=\frac{2.2\times {{10}^{6}}}{n}m/s\]or\[{{V}_{n}}\propto \frac{1}{n}\] As principal quantum number increases, velocity decreases.                                


You need to login to perform this action.
You will be redirected in 3 sec spinner