A) \[\frac{1}{4}\]
B) \[\frac{2}{3}\]
C) \[\frac{1}{5}\]
D) \[\frac{1}{3}\]
Correct Answer: B
Solution :
Total possible event when one ball is taken out \[{{=}^{3}}{{C}_{1}}\] Let E : The event of 1 white ball coming out No. of ways to 1 white ball coming out\[{{=}^{2}}{{C}_{1}}\] \[\therefore \]\[P(E)=\frac{^{2}{{C}_{1}}}{^{3}{{C}_{1}}}=\frac{2}{3}\]
You need to login to perform this action.
You will be redirected in
3 sec
