A) 17.8 M
B) 12.0 M
C) 10.5M
D) 15.7M
Correct Answer: A
Solution :
95% \[{{H}_{2}}S{{O}_{4}}\] by weight means \[100g{{H}_{2}}S{{O}_{4}}\] solution contains \[95\,g\,{{H}_{2}}S{{O}_{4}}\]by mass. Molar mass of \[\,{{H}_{2}}S{{O}_{4}}=98g\,mo{{l}^{-1}}\] Moles in \[95g=\frac{95}{98}=0.969\]mole Volume of\[100g{{H}_{2}}S{{O}_{4}}\] \[=\frac{\text{mass}}{\text{density}}=\frac{100g}{1.834g\,c{{m}^{-1}}}\] \[=54.52c{{m}^{3}}=54.52\times {{10}^{-3}}L\] \[\text{Molarity=}\frac{\text{Moles}\,\text{of}\,\text{solute}}{\text{Volme}\,\text{of}\,\text{solute}\,\text{in}\,\text{L}}\] \[\text{=}\frac{0.969}{54.52\times {{10}^{-3}}}=17.8M\]
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