A) \[434J/k{{g}^{-o}}C\]
B) \[378J/k{{g}^{-o}}C\]
C) \[315J/k{{g}^{-o}}C\]
D) \[476J/k{{g}^{-o}}C\]
Correct Answer: A
Solution :
Q given = Q used \[0.2\times S\times (150-40)=150\times 1\times (40-27)\] \[+25\times (40-27)\] \[0.2\times S\times 110=150\times 13+25\times 13\] \[S=\frac{13\times 25\times 7}{0.2\times 110}\] \[S=434\]
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