A) (2 and 4) and (2 and 4)
B) (4 and 2) and (4 and 2)
C) (4 and 2) and (2 and 4)
D) (2 and 2) and (2 and 2)
Correct Answer: B
Solution :
Peroxodisulphuric acid \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]\[HO-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-O-O-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-OH\] Pyrosulphuric acid \[{{H}_{2}}{{S}_{2}}{{O}_{7}}:\] \[HO-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-O-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-OH\]
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