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JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

  • question_answer
    A particle which is simultaneously subjected to two perpendicular simple harmonic motions represented by\[;x={{a}_{1}}\cos \omega t\]and\[y={{a}_{2}}\cos 2\omega t\]traces a curve given by:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A)                

    B)

    C)                                                 

    D)

    Correct Answer: B

    Solution :

    Two perpendicular S.H.Ms are \[x={{a}_{1}}\cos \omega t\]                                        ....(1) and\[y={{a}_{2}}2\cos \omega t\]                            ....(2) From eqn (1)\[\frac{x}{{{a}_{1}}}=\cos wt\]and from eqn (2) \[\frac{y}{{{a}_{2}}}=2\cos \omega t\]\[\therefore \]\[y=2\frac{{{a}_{2}}}{{{a}_{1}}}x\]


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