[JEE Main Online Paper ( Held On 09 Apirl 2014 )
A) 520 nm
B) 540 nm
C) 560 nm
D) 580 nm
Correct Answer: B
Solution :
Given \[t=1.8\times {{10}^{-6}}m\] \[\mu =1.6\]n = 2 (from figure) Applying formula \[(\mu -1)t=n\lambda \] \[(1.6-1)\times 1.8\times {{10}^{-6}}=2\lambda \] or,\[\lambda =\frac{1.8\times {{10}^{-6}}\times 0.6}{2}\]\[=540nm\]
You need to login to perform this action.
You will be redirected in
3 sec
