A) 432
B) 108
C) 36
D) 18
Correct Answer: B
Solution :
With 3 at unit place, total possible four digit number (without repetition) will be 3 ! = 6 With 4 at unit place, total possible four digit numbers will be 3! = 6 With 5 at unit place, total possible four digit numbers will be 3! = 6 With 6 at unit place, total possible four digit numbers will be 3! = 6 Sum of unit digits of all possible numbers \[=6\times 3+6\times 4+6\times 5+6\times 6\] \[=6[3+4+5+6]\] = 6 [18] = 108You need to login to perform this action.
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