question_answer

Identify the gate and match A, B, Y in bracket to check.   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

A) AND (A = 1, B = 1, Y = 1)

B) OR (A = 1, B = 1, Y = 0)

C) NOT (A = 1, B = 1, Y = 1)

D) XOR (A = 0, B = 0, Y = 0)

Correct Answer: A

Solution :

\[Y=\overline{\overline{AB}.\overline{AB}}=\overline{\overline{AB}}+\overline{\overline{AB}}=AB+AB=AB\] In this case output Y is equivalent to AND gate.