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JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

  • question_answer
    The solubility of \[{{N}_{2}}\]in water at 300 K and 500 torr partial pressure is 0.01 g \[{{\text{L}}^{\text{-1}}}\]. The solubility (in g \[{{\text{L}}^{\text{-1}}}\]) at 750 torr partial pressure is :   JEE Main Online Paper (Held On 09 April 2016)

    A) 0.02                       

    B) 0.015

    C) 0.0075                  

    D) 0.005

    Correct Answer: B

    Solution :

                    According to Henery law\[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{S}_{1}}}{{{S}_{2}}}\] \[\therefore \]\[{{S}_{1}}\And {{S}_{2}}\]are solubility of gas (g/L) \[\frac{500}{750}=\frac{0.01}{{{S}_{2}}}\] \[\therefore \]\[{{S}_{2}}=\frac{750\times 0.01}{500}=0.015g/L\]


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