A) \[4x+5y-6=0\]
B) \[5x+2y+4=0\]
C) \[2x-3y+10=0\]
D) \[3x+4y-3=0\]
Correct Answer: C
Solution :
Required circle is \[{{(x-0)}^{2}}+{{(y-2)}^{2}}+\lambda (x)=0\]it passes (. 2, 4) \[\therefore \]\[4+4-2\lambda =0\] \[\lambda =4\] \[\therefore \] circle is \[{{x}^{2}}+{{y}^{2}}-4y+4x+4=0\] centre (.2, 2) which satisfy \[\text{2x-3y}+\text{1}0=0\]
You need to login to perform this action.
You will be redirected in
3 sec
