A) 9 mm
B) 3 mm
C) 4.5 mm
D) 1.5 mm
Correct Answer: A
Solution :
\[a=0.1\,mm={{10}^{-4}}\] \[\lambda =600k\,\times \,{{10}^{-10}}\,=6\times {{10}^{-7}}\] for 3rd dark \[D=0.5\,m\] \[\sin \theta =\frac{3\lambda }{a}\,=\frac{x}{D}\] \[x=\frac{3\lambda D}{a}\] \[=\frac{3\times 6\times {{10}^{-7}}\,\times 0.5}{{{10}^{-4}}}\] \[=\,9\,mm\] \[a\sin \theta \,=3\lambda \]
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