JEE Main & Advanced JEE Main Paper Phase-I (Held on 08-1-2020 Morning)

  • question_answer
    The graph which depicts the results of Rutherford gold foil experiment with \[\alpha \]-particle is \[\theta \] : Scattering angle Y: Number of scattered \[\alpha \]-particles detected (Plots are schematic and not to scale) [JEE MAIN Held On 08-01-2020 Morning]

    A)

    B)

    C)

    D)

    Correct Answer: D

    Solution :

    [d] In 1911, Ernest Rutherford publish a formula. Which indicates that number of particles (Y) that would be deflected by an angle ?\[\theta \]? due to scattering is \[{{Y}_{(\theta )}}=\frac{K}{{{\sin }^{4}}\frac{\theta }{2}}\] Where K = constant \[\therefore \] Corresponding graph.


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