A) Only when the Gaussian surface is an equipotential surface and \[\left| {\vec{E}} \right|\] is constant on The surface.
B) Only when\[\left| {\vec{E}} \right|=\] constant on the surface.
C) Only when the Gaussian surface is a equipotential surface.
D) For any choice of Gaussian surface.
Correct Answer: A
Solution :
[a] By Gauss law \[\oint{\vec{E}\cdot \overrightarrow{dA}}=\frac{{{Q}_{in}}}{{{\varepsilon }_{0}}}\] If \[\left| {\vec{E}} \right|=\frac{{{Q}_{in}}}{\left| {\vec{A}} \right|{{\varepsilon }_{0}}}\] or \[\left| {\vec{E}} \right|\left| {\vec{A}} \right|=\frac{{{Q}_{in}}}{{{\varepsilon }_{0}}}\] Then \[\vec{E}||\vec{A}\] \[\therefore \] Surface is equipotential too.
You need to login to perform this action.
You will be redirected in
3 sec
