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JEE Main & Advanced JEE Main Paper Phase-I (Held on 08-1-2020 Morning)

  • question_answer
    A leak proof cylinder of length 1 m, made of a Metal which has very low coefficient of expansion is floating vertically in water at \[0{}^\circ C\]such that its height above the water surface is 20 cm. When the temperature of water is increased to \[4{}^\circ C,\] the height of the cylinder above the water surface becomes 21 cm. The density of water at \[T=4{}^\circ C,\]relative to the density at \[T=0{}^\circ C\]is close to                  [JEE MAIN Held On 08-01-2020 Morning]

    A) 1.04

    B) 1.03

    C) 1.26

    D) 1.01

    Correct Answer: D

    Solution :

    [d] Law of floatation \[\frac{{{V}_{i}}}{V}=\frac{{{\rho }_{body}}}{{{\rho }_{liquid}}}\] In given case \[\therefore \frac{{{h}_{1}}}{{{h}_{2}}}=\frac{\left( {{\rho }_{4{}^\circ c}} \right)}{\left( {{\rho }_{0{}^\circ c}} \right)}\left[ {{\rho }_{body}}=\text{constant} \right]\] \[\frac{{{p}_{4{}^\circ c}}}{{{p}_{0{}^\circ c}}}\left( \frac{100-20}{100-21} \right)=\frac{80}{79}=1.01\]


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