JEE Main & Advanced JEE Main Paper Phase-I (Held on 08-1-2020 Morning)

  • question_answer
    When gypsum is heated to 393 K, it forms                               [JEE MAIN Held On 08-01-2020 Morning]

    A) Anhydrous \[CaS{{O}_{4}}\]

    B) Dead burnt plaster

    C) \[CaS{{O}_{4}}\cdot 5{{H}_{2}}O\]

    D) \[CaS{{O}_{4}}\cdot 0.5{{H}_{2}}O\]

    Correct Answer: D

    Solution :

    [d] Gypsum on heating to 393 K forms plaster of Paris \[CaS{{O}_{4}}\cdot 2{{H}_{2}}O\xrightarrow{393K}CaS{{O}_{4}}\cdot 0.5{{H}_{2}}O+1.5{{H}_{2}}O\]


You need to login to perform this action.
You will be redirected in 3 sec spinner